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2 votes
Divide:

(x² + 3x²-x+4) ÷ (x-1)
If there is a remainder, express the result in the form q(x)+r(x)/b(x)

User Alif
by
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2 Answers

0 votes

Answer:

To divide (x² + 3x² - x + 4) by (x - 1), we can use long division:

markdown

C

4x + 5

____________

x - 1| x² + 3x² - x + 4

-4x² + 4x

___________

7x + 4

Therefore, the result of the division is:

(x² + 3x² - x + 4) ÷ (x - 1) = 4x + 5 + (7x + 4)/(x - 1)

Since there is a remainder of (7x + 4)/(x - 1), we can express the result in the form q(x) + r(x)/b(x) as:

(x² + 3x² - x + 4) ÷ (x - 1) = 4x + 5 + (7x + 4)/(x - 1) = 4x + 5 + (7x + 4) ÷ (x - 1)

User Sam Borick
by
7.4k points
5 votes

Answer:

4x+3+
(7)/(x-1)

Explanation:

User Paul Annetts
by
8.1k points