L1
is parallel to L2
, and therefore m∠t=m∠x
and m∠w=m∠y
.
Which can be used to show that the sum of the interior angles of the triangle is 180°
?
Responses
A straight angle has a measure of 180°
, so m∠t+m∠v+m∠w=180°
, and since m∠t=m∠x
and m∠w=m∠y
, m∠x+m∠y+m∠v=180°
.
A straight angle has a measure of , so m∠t+m∠v+m∠w=180°
, and since m∠t=m∠x
, , and m∠w=m∠y
, m∠x+m∠y+m∠v=180°
.
Alternate interior angles are equal, so m∠t=m∠x
and m∠w=m∠y
, and since ∠x
and ∠y
are supplementary, m∠x+m∠y+m∠v=180°.
Alternate interior angles are equal, so m∠t=m∠x
, , and m∠w=m∠y
, and since ∠x
and ∠y
, , are supplementary, m∠x+m∠y+m∠v=180°.
Since m∠t=m∠x
and m∠w=m∠y
, and m∠v=90°
, the sum of the angles is m∠x+m∠y+m∠v=180°.
Since m∠t=m∠x
and m∠w=m∠y
, and m∠v=90°
, the sum of the angles is m∠x+m∠y+m∠v=180°.
The interior angles of a triangle are complementary, so since m∠t=m∠x
and m∠w=m∠y
, m∠x+m∠y+m∠v=180°