Question

steam enters a steady-flow turbine with a mass flow rate of 13 kg/s at 6008c, 8 mpa, and a negligible velocity. the steam expands in the turbine to a saturated vapor at 300 kpa where 10 percent of the steam is removed for some other use. the remainder of the steam continues to expand to the turbine exit where the pressure is 10 kpa and quality is 85 percent. if the turbine is adiabatic, determine the rate of work done by the steam during this process.

Answer 1

The rate of work done by the steam during this process is 9300.2 kW.

Step-by-step explanation:

To determine the rate of work done by the steam during the process, we need to calculate the change in enthalpy of the steam. First, we calculate the initial enthalpy of the steam using the steam tables at 600°C and 8 MPa. The enthalpy is 3401.7 kJ/kg.

Then, we calculate the final enthalpy of the steam using the steam tables at 10 kPa and 85% quality. The enthalpy is 2686.3 kJ/kg. Now we can calculate the change in enthalpy by subtracting the final enthalpy from the initial enthalpy: 3401.7 kJ/kg - 2686.3 kJ/kg = 715.4 kJ/kg. Finally, we can calculate the rate of work done by multiplying the mass flow rate of the steam (13 kg/s) by the change in enthalpy: 13 kg/s * 715.4 kJ/kg = 9300.2 kW.