Final answer:
The letter 's' from the word 'senselessness' has the highest probability of selection at 5/12, while the letter 'l' has the lowest probability of 1/12.
Step-by-step explanation:
To determine which letter from the word 'senselessness' has the greatest and least probability of being selected from a bag, we first need to count how many times each letter appears in the word. 'Senselessness' consists of the letters: s, e, n, and l. The counts for each letter are as follows: s appears 5 times, e appears 4 times, n appears 2 times, and l appears 1 time. The total number of letters is 12. Therefore, the letter s has the greatest probability of being selected with a probability of 5/12, and the letter l has the least probability of being selected with a probability of 1/12.