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X3 − 3x2 + 2x − 8 factored

User Montmons
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1 Answer

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Answer:

(x^2 - 2)(x - 4).

Explanation:

To factor the expression x^3 - 3x^2 + 2x - 8, we can use a combination of grouping and factoring by grouping.

First, we can group the first two terms and the last two terms together:x^3 - 3x^2 + 2x - 8 = (x^3 - 3x^2) + (2x - 8)

Next, we can factor out x^2 from the first group and 2 from the second group:x^3 - 3x^2 + 2x - 8 = x^2(x - 3) + 2(x - 4)

Now, we can see that both terms have a common factor of (x - 4), so we can factor that out:x^3 - 3x^2 + 2x - 8 = (x^2 - 2)(x - 4)

Therefore, the factored form of the expression x^3 - 3x^2 + 2x - 8 is (x^2 - 2)(x - 4).

User Tom Klino
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