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What does the constant 0.98 reveal about the rate of change of the quantity?

What does the constant 0.98 reveal about the rate of change of the quantity?-example-1
What does the constant 0.98 reveal about the rate of change of the quantity?-example-1
What does the constant 0.98 reveal about the rate of change of the quantity?-example-2
What does the constant 0.98 reveal about the rate of change of the quantity?-example-3
User Kristian Haga
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1 Answer

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The given function is:


f(x)=780(0.98)^(10t)

It is required to state what the constant 0.98 reveal about the rate of change of the quantity by completing the given statement:

The function is exponentially at a rate of every .

Notice from the given exponential function that the factor is 0.98.

Since it is less than 1, it implies that it is an exponential DECAY.

Subtract the factor 0.98 from 1 to get the decay rate:


1-0.98=0.02=0.02*100\%=2\%

Unit of t: decades

The exponent is 10t.

The reciprocal is 1/10.

Hence, the time frame of rate is: 1/10 of a decade.

This is equivalent to a year.

The complete statement is, therefore:

The function is decaying exponentially at a rate of 2% every year.

User Neglected Sanity
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