Answer:
888
Explanation:
Surface area of triangular prism + Surface area of cuboid MINUS base area of triangular prism
A=288 + 648 - 48
1. Surface area of triangular prism = 2(Area of triangular base) + (Perimeter of triangular base) x (Height of prism)
A=2Ab+(a+b+c)h
or
triangular prism Surface area = 2((1/2)bh) + (b1 + b2 + b3)h
triangular prism Surface area = 2((1/2)12*8) + (12 + 10 + 10)6
triangular prism Surface area = 2((1/2)96) + 96)
triangular prism Surface area = 2(48 + 96)
triangular prism Surface area = 2(144)
triangular prism Surface area = 288
2. Surface area of cuboid
Surface Area = 2(lw + lh + wh)
Surface Area = 2(18*6 + 18*9 + 6*9)
Surface Area = 2(108 + 162 + 54)
Surface Area = 2(324)
Surface Area = 648
3. base area of triangular prism
base area of triangular prism = ((1/2)b*h)
base area of triangular prism = ((1/2)12*8)
base area of triangular prism = ((1/2)96)
base area of triangular prism = 48
SA=288 + 648 - 48=888
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