Answer:
The balanced chemical equation for the reaction of nitrogen gas (N2) with hydrogen gas (H2) to form ammonia gas (NH3) is:
N2 + 3H2 → 2NH3
According to the stoichiometry of the reaction, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Therefore, the ratio of N2 to NH3 is 1:2.
To find the amount of NH3 produced when 649 grams of N2 react completely, we need to use the mole ratio between N2 and NH3:
1 mol N2 → 2 mol NH3
First, we need to calculate the number of moles of N2 in 649 grams:
Number of moles of N2 = Mass of N2 / Molar mass of N2
= 649 g / 28.014 g/mol
= 23.173 mol N2
According to the stoichiometry of the reaction, 1 mole of N2 reacts to produce 2 moles of NH3. Therefore, the number of moles of NH3 produced can be calculated as:
Number of moles of NH3 = 2 x Number of moles of N2
= 2 x 23.173 mol
= 46.346 mol NH3
Finally, we can use the molar mass of NH3 to convert the number of moles to grams:
Mass of NH3 = Number of moles of NH3 x Molar mass of NH3
= 46.346 mol x 17.031 g/mol
= 789.5 g NH3
Therefore, 649 grams of N2 react completely to produce 789.5 grams of NH3.