Question

In 0.5hours, a supersonic jet flew 1,000kilometers to the east at a constant velocity. During the flight, the jet passed an airplane that was moving at 903 kilometers per hour. What was the jet's velocity?

Answer 1

We can use the formula:

velocity = distance / time

To find the velocity of the supersonic jet.

The distance traveled by the jet is 1,000 kilometers, and the time taken is 0.5 hours. So:

velocity = 1,000 km / 0.5 hours

velocity = 2,000 km/hour

Now, we need to find the velocity of the airplane that the jet passed during its flight. The airplane's velocity is given as 903 km/hour.

Since the jet and the airplane were traveling in opposite directions, we can add their velocities to find the relative velocity between them:

relative velocity = velocity of jet + velocity of airplane

relative velocity = 2,000 km/hour + 903 km/hour

relative velocity = 2,903 km/hour

So, the velocity of the supersonic jet is 2,000 km/hour.