Question

Can you show me like on a same graph like mine

Answer 1

Given the general quadratic equation:

`ax^2+bx+c=0`

The general solution of the quadratic equation is given by the expression:

`x=(-b\pm√(b^2-4ac))/(2a)`

From the problem, we have the quadratic equation:

`3x{}^2+2x-225=0`

Identifying the coefficients:

`\begin{gathered} a=3 \\ b=2 \\ c=-225 \end{gathered}`

Then, using the general solution formula:

`\begin{gathered} x=(-2\pm√(4+2700))/(6)=(-2\pm52)/(6) \\ \\ \Rightarrow x_1=(25)/(3) \\ \\ \Rightarrow x_2=-9 \end{gathered}`

And the solutions on the number line are: