Answer:
x = - 2, x = - 1 , x = 1
Explanation:
x³ + 2x² - x - 2 = 0 ( factor first/second and third/fourth terms )
x²(x + 2) - 1 (x + 2) = 0 ← factor out x + 2) from each term
(x + 2)(x² - 1) = 0 ← x² - 1 is a difference of squares and factors as (x + 1)(x - 1)
(x + 2)(x + 1)(x - 1) = 0
equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x + 1 = 0 ⇒ x = - 1
x - 1 = 0 ⇒ x = 1