Question

A party rental company has chairs and tables for rent.The total cost to rent 5 chairs and 3 tables is $39.The total cost to rent 2 chairs and 12 tables is $129.What is the cost to rent each chair and each table?

Answer 1

The cost to rent each chair is $0.6.

The cost to rent each table is $10.5.

Explanation:

Let's denote the cost of renting one chair as c and the cost of renting one table as t. Then we can write two equations based on the given information:

5c + 3t = 39 (equation 1)

2c + 12t = 129 (equation 2)

We can use these equations to solve for c and t. One way to do this is to solve for one variable in terms of the other in one of the equations, and then substitute that expression into the other equation. For example, we can solve equation 1 for c:

5c + 3t = 39

5c = 39 - 3t

c = (39 - 3t)/5

Now we can substitute this expression for c into equation 2:

2c + 12t = 129

2[(39 - 3t)/5] + 12t = 129

Simplifying and solving for t, we get:

(78 - 6t)/5 + 12t = 129

78 - 6t + 60t = 645

54t = 567

t = 10.5

So the cost of renting one table is $10.5. We can substitute this value back into equation 1 to solve for c:

5c + 3t = 39

5c + 3(10.5) = 39

5c = 3

c = 0.6

Therefore, the cost of renting one chair is $0.6.

In summary, the cost to rent each chair is $0.6 and the cost to rent each table is $10.5.