Question

Write the equation of the line a) in slope-intercept &

b) in standard form, perpendicular to 3x-y=-5 & passing
through point (3,-2).

Answer 1

a. y = -1/3x - 1

b x + 3y = -3

Explanation:

the equation 3x - y = -5 => y = 3x + 5 has slope of 3

Lines that are perpendicular will have negative reciprocal slopes.

so slope of perpendicular line to 3x - y = -5 is -1/3

y = mx + b

-2 = -1/3(3) + b

- 2 = -1 + b

b = -1

a. y = -1/3x - 1

b 1/3x + y = -1 or x + 3y = -3