Answer:
1699.3 mmHg.
Step-by-step explanation:
We can use the combined gas law to solve this problem:
(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature. We can rearrange the equation to solve for P2:
P2 = (P1 × V1 × T2) ÷ (V2 × T1)
First, we need to convert the temperatures to Kelvin:
T1 = 25 + 273.15 = 298.15 K
T2 = 75 + 273.15 = 348.15 K
Now we can plug in the values:
P2 = (P1 × V1 × T2) ÷ (V2 × T1)
P2 = (900.0 mmHg × 32.5 L × 348.15 K) ÷ (12.0 L × 298.15 K)
P2 = 1699.3 mmHg
Therefore, the pressure exerted by the gas at 25 °C is 1699.3 mmHg.