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(4x3 – 6x2 – 4x + 8) ÷ (2x – 1)
Use long division to find each quotient

1 Answer

4 votes

Explanation:

We can use long division to divide the polynomial (4x³ - 6x² - 4x + 8) by the binomial (2x - 1).

2x² + 2x - 4

2x - 1 | 4x³ - 6x² - 4x + 8

- (4x³ - 2x²)

---------------

-4x² - 4x

+ ( -4x² + 2x )

--------------

-2x + 8

- (-2x + 1)

----------

7

Therefore, the quotient is 2x² + 2x - 4, and the remainder is 7.

User SledgeHammer
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