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A 750 mL balloon at 20 °C and a pressure of 800 mmHg is allowed to expand to 3250 mL and a pressure of 350 mmHg. What is the new temperature of the gas?

User Rougher
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1 Answer

3 votes

Answer:

-24 °C

Step-by-step explanation:

We can use the combined gas law equation:

(P₁V₁)/T₁ = (P₂V₂)/T₂

where P is pressure, V is volume, and T is temperature, and subscripts 1 and 2 represent initial and final conditions.

Plugging in the values:

P₁ = 800 mmHg

V₁ = 750 mL

T₁ = 20 °C + 273.15 = 293.15 K

P₂ = 350 mmHg

V₂ = 3250 mL

T₂ = ?

((800 mmHg)(750 mL))/293.15 K = ((350 mmHg)(3250 mL))/T₂

Simplifying and solving for T₂:

T₂ = ((350 mmHg)(3250 mL))(293.15 K)/((800 mmHg)(750 mL))

T₂ ≈ 249 K

Converting back to Celsius:

T₂ ≈ -24 °C

Therefore, the new temperature of the gas is approximately -24 °C.

User Kioleanu
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