Answer:
Step-by-step explanation:
Assuming that "green-haired Zork" refers to a trait that is controlled by a single gene with two alleles, where green hair is dominant and yellow hair is recessive, the genotypes and phenotypes of the possible offspring can be determined using a Punnett square.
Let G represent the dominant green hair allele and g represent the recessive yellow hair allele.
The genotypes of the two parent works are both Gg, meaning they are heterozygous for the green hair trait.
From the Punnett square, we can see that the possible genotypes of the offspring are GG, Gg, and gg.
GG individuals would be homozygous dominant for green hair.
Gg individuals would be heterozygous for green hair, like their parents.
gg individuals would be homozygous recessive for yellow hair.
The possible phenotypes of the offspring can also be determined from their genotypes:
GG and Gg individuals would have green hair, which is the dominant phenotype.
gg individuals would have yellow hair, which is the recessive phenotype.
Therefore, the possible genotypes and phenotypes of the offspring are:
25% GG green haired zorks
50% Gg green haired zorks
25% gg yellow haired zorks