Answer:
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Let the five integers be x, x + 2, x + 4, x + 6, x + 8.
The sum of the first three integers is 7 more than the sum of the last two. Set up equation and solve for x:
- x + x + 2 + x + 4 = 7 + x + 6 + x + 8
- 3x + 6 = 2x + 21
- x = 21 - 6
- x = 15
Hence the integers are: