Question

30x+50y=420
15x+35y=220
Use elimination method

Answer 1

y = 1, x = 37/3

Explanation:

30x + 50y = 420

-2(15x + 35y = 220)

x cancel each other (30x - 30x)

50y - 70y = -20y

220 * -2 = -440

420 - 440 = -20

-20 / -20 = 1

y = 1

420 - 50 = 370

370 / 30 = 37/3

x = 37/3

Answer 2

To solve the system of equations using the elimination method, we want to eliminate one of the variables by adding or subtracting the two equations. We can then use the resulting equation to solve for the remaining variable, and then substitute that value back into one of the original equations to solve for the other variable.

In this case, we notice that if we multiply the second equation by 2, we can eliminate the variable x by subtracting the two equations:

30x + 50y = 420 (equation 1)

15x + 35y = 220 (equation 2)

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30x + 70y = 440 (2 x equation 2)

- 30x - 50y = -420 (equation 1)

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20y = 20

Now we have an equation involving only y. Solving for y, we get:

20y = 20

y = 1

Substituting this value back into one of the original equations, we can solve for x:

15x + 35y = 220 (equation 2)

15x + 35(1) = 220

15x + 35 = 220

15x = 185

x = 185/15

x = 37/3

Therefore, the solution to the system of equations is x = 37/3 and y = 1.