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Find KL please I really need the help

Find KL please I really need the help-example-1
User Kechol
by
8.0k points

1 Answer

5 votes

Answer:

Explanation:

In
\triangle JLM,


tan51=(JL)/(JM)


tan51=(JL)/(14)


JL=14tan51=17.2886

In
\triangle JKL,


cos72=(KL)/(JL) \\


cos72=(KL)/(17.2886)


KL=17.2886cos72=5.34

User Vardhan
by
7.7k points

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