60.4k views
7 votes
Solve the system of equations 6x+3y=12 and 5x+y=7

User Baldwin
by
7.5k points

2 Answers

7 votes

Answer:

x = 1; y = 2

Explanation:

To find x:

Multiply (5x+y=7) by 3 to get the y's in both equation the same, and you will get 15x+3y=21.

Now the y's cancel out. Subtract the remaining equations: (15x=21) - (6x=12) and you get 9x = 9. Divide everything by 9 and you get x=1.

To find y:

You can substitute 1 for x in either equation. I will use (5x+y=7).

Substitute the 1 for x: 5(1)+y=7

Simplify: 5+y=7

Put like terms on the same side by subtracting 5 from both sides: y=2

Check:

6(1) + 3(2) = 12

6 + 6 = 12

12 = 12 - this is right

5(1) + (2) = 7

5 + 2 = 7

7 = 7 - this is right

User Igor Kraskynlykov
by
8.7k points
8 votes
6x+3y = 12
Solving for x
3(2x+y)=12
2x+y=12/3
2x+y=4
2x=4-y
X=4-y/2
User JohnK
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories