Question

If 8.4 moles of sodium chloride were given in the laboratory, how

many moles of aluminum chloride would you expect the reaction to
produce?

Answer 1

2.8 moles

Steps

NaCl moles to AlCl3

1 Al + 3NaCl + 3H2O → 1 AlCl3 + 3H2 + 3NaO

3 NaCl gives 1 AlCl3

so it's 1/3

8.4 ÷ 3

if 8.4 moles of sodium chloride were given in the laboratory, how

many moles of aluminum chloride, would you expect the reaction to

produce?

The balanced chemical equation for the reaction is:

Al + 3NaCl + 3H2O → AlCl3 + 3H2 + 3NaO

According to the stoichiometry of the equation, 1 mole of aluminum reacts with 3 moles of sodium chloride to produce 1 mole of aluminum chloride. Therefore, the number of moles of aluminum chloride produced can be calculated as follows:

Moles of aluminum chloride produced = Moles of NaCl / 3

Moles of aluminum chloride produced = 8.4 / 3

Moles of aluminum chloride produced = 2.8 moles

Therefore, the reaction would produce 2.8 moles of aluminum chloride if 8.4 moles of sodium chloride were given in the laboratory.

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