Answer
2.8 moles
Steps
NaCl moles to AlCl3
1 Al + 3NaCl + 3H2O → 1 AlCl3 + 3H2 + 3NaO
3 NaCl gives 1 AlCl3
so it's 1/3
8.4 ÷ 3
if 8.4 moles of sodium chloride were given in the laboratory, how
many moles of aluminum chloride, would you expect the reaction to
produce?
The balanced chemical equation for the reaction is:
Al + 3NaCl + 3H2O → AlCl3 + 3H2 + 3NaO
According to the stoichiometry of the equation, 1 mole of aluminum reacts with 3 moles of sodium chloride to produce 1 mole of aluminum chloride. Therefore, the number of moles of aluminum chloride produced can be calculated as follows:
Moles of aluminum chloride produced = Moles of NaCl / 3
Moles of aluminum chloride produced = 8.4 / 3
Moles of aluminum chloride produced = 2.8 moles
Therefore, the reaction would produce 2.8 moles of aluminum chloride if 8.4 moles of sodium chloride were given in the laboratory.
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