Question

Please help!!!! The roots of x^2-2x-2=0 are A.1+square root of 3 B.1+square root of 12 or C.No real roots

Answer 1

A

Explanation:

We have the equation:

`x^2-2x-2=0`

We can use the quadratic formula. In this case, a = 1, b = -2, and c = -2. Hence:

`\displaystyle x=(-(-2)\pm√((-2)^2-4(1)(-2)))/(2(1))`

Evaluate:

`\displaystyle x=(2\pm√(12))/(2)`

Simplify:

`√(12)=√(4)\cdot√(3)=2√(3)`

Hence:

`\displaystyle x=(2\pm2√(3))/(2)`

Divide:

`x=1\pm\sqrt3`

The correct answer is A.