Question

.5 An average human weighs about 650 N. If two such generichumans each carried 1.0 coulomb of excess charge, one positive andone negative, how far apart would they have to be for the electricattraction between them to equal their 650-N weight?

Answer 1

To calculate the distance between two point charges, we can use Coulomb's Law. The two point charges must be 2.60 meters apart for the electric attraction between them to equal their 650-N weight.

Step-by-step explanation:

To calculate the distance between two point charges, we can use Coulomb's Law. According to Coulomb's Law, the electric force between two point charges is given by the equation:

F = k(q1q2) / r2

Where F is the force, k is the electrostatic constant (9 x 109 Nm2/C2), q1 and q2 are the charges of the two point charges, and r is the distance between them.

In this case, we have a force of 1.00 N and charges of 75.0 nC for each point charge. We can rearrange the equation to solve for the distance r:

r = sqrt((k(q1q2)) / F)

Substituting the values, we get:

r = sqrt((9 x 109 Nm2/C2)(75.0 x 10-9 C)2) / 1.00 N) = 2.60 m

Therefore, the two point charges must be 2.60 meters apart for the electric attraction between them to equal their 650-N weight.

Answer 2

To calculate the distance at which the electric attraction of 650 N equals the weight of the individuals, use Coulomb's Law. With a force set to 650 N and the charges at 1.0 C each, the individuals must be approximately 0.117 meters or 117 centimeters apart.

Step-by-step explanation:

To find out how far apart two persons with 1.0 coulomb of excess charge each must be for the electric attraction between them to equal their 650-N weight, we use Coulomb's Law which is expressed as F = k * |q1 * q2| / r^2, where F is the force, k is Coulomb's constant (8.9875 x 109 Nm2/C2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

We set the force F to be equal to the weight of the average human, which is 650 N, and solve for r:

• F = k * |q1 * q2| / r^2
• 650 N = (8.9875 x 109 Nm2/C2) * (1.0 C * 1.0 C) / r2
• r2 = (8.9875 x 109 Nm2/C2) * (1.0 C * 1.0 C) / 650 N
• r2 = (8.9875 x 109) / 650
• r = sqrt((8.9875 x 109) / 650)
• r ≈ 0.117 meters or 117 centimeters

Therefore, two people must be approximately 0.117 meters or 117 centimeters apart for the electric attraction to equal the force of gravity acting on them.