Question

Line that passes through point (3,-1) and is parallel to the line y=1/3x-3

Answer 1

Explanation:

`y=(1)/(3) x-3` has
`m=(1)/(3)` (gradient), so a line parallel will have same gradient.

Using point-slope form of line equation:

`y-y_1 =m(x-x_1)` with
`m=(1)/(3)` and point
`(3,-1)` we get:

`y+1=(1)/(3) (x-3)` (can be left in this form if you want)

`y=(1)/(3) x-2` (if you prefer answer in same form as question)