Question

1) How many moles of N are in 0.181 g of N2O?

2) A chemist requires 0.39 mol Na2CO3 for a reaction. How many grams does this correspond to?
3) How many moles of Fe2O3 are in 191 g of the compound?

Answer 1

Answer:1.) 0.00822, 2.) 41.33 3.) 1.196

Step-by-step explanation:

1.) Molar mass of N2O: 2(14.01) + 16.00= 44.02g

0.181g N2O * ( 1 mol N20/ 44.02g N2O) * (2 mol N/ 1 mol N2O)= .00822

2.)Molar mass of Na2CO3: 2(22.99)+ 12.01 + 3(16.00)= 105.99g

(0.39 mol Na2CO3)* (105.99g of Na2CO3/ 1 mol of Na2CO3)= 41.331

3)Molar mass of Fe2O3: 2(55.85)+3(16)= 159.7g

(191g Fe2O3) * ( 1 mole Fe2O3/ 159.7g Fe2O3 )= 1.196