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How many GRAMS of carbon are present in 3.17 moles of carbon monoxide

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Answer:

38.07 grams

Step-by-step explanation:

To solve this problem, we need to use the molar mass of carbon monoxide (CO) to convert from moles to grams.

The molar mass of CO is:

M(CO) = M(C) + M(O) = 12.01 g/mol + 15.99 g/mol = 28.00 g/mol

This means that one mole of CO has a mass of 28.00 grams.

To find the mass of carbon present in 3.17 moles of CO, we need to multiply the number of moles by the molar mass of carbon and then convert to grams:

mass of carbon = 3.17 moles x (12.01 g/mol/1 mole) = 38.07 grams

Therefore, there are 38.07 grams of carbon present in 3.17 moles of carbon monoxide.

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