162k views
1 vote
A long, straight wire carries a charge density of 142 μC/m. Find the magnitude of the electric field 75.0 cm from the axis of the wire.

1 Answer

4 votes

We can use the formula for the electric field due to a line of charge:

E = k λ / r

where E is the electric field, k is Coulomb's constant, λ is the charge density, and r is the distance from the wire.

Plugging in the given values:

E = (9 x 10^9 N·m^2/C^2) (142 x 10^-6 C/m) / (0.75 m)

E = 1.90 x 10^3 N/C

Therefore, the magnitude of the electric field 75.0 cm from the axis of the wire is 1.90 x 10^3 N/C.

User Queena
by
7.8k points