Question

The circumference of the inner circle is 22ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use 22/7

for pie

Answer 1

18.84 ft

Explanation:

The circumference of a circle is given by the formula C = 2πr, where C is the circumference and r is the radius of the circle.

Since we know the circumference of the inner circle is 22 ft, we can find its radius as follows:

C = 2πr

22 = 2πr

r = 22/(2π)

r ≈ 3.5 ft

The radius of the outer circle is the sum of the radius of the inner circle and the distance between the two circles, which is 3 ft. Therefore, the radius of the outer circle is:

r = 3.5 + 3

r = 6.5 ft

The circumference of the outer circle is:

C = 2πr

C = 2π(6.5)

C ≈ 40.84 ft

The difference between the circumference of the outer circle and the circumference of the inner circle is:

40.84 - 22 = 18.84 ft

Therefore, the circumference of the outer circle is greater than the circumference of the inner circle by approximately 18.84 feet.