Question

The average age for individuals with concealed handgun licenses in the county is p = 42.6 years with a standard deviation of sigma = 12 The distribution is approximately normal A researcher obtained a sample of n = 36 individuals with concealed handgun licensesThe average age for those in the sample was M = 607 this a reasonable for a sample of t_{n} = 38 or is this sample mean an extreme value? (Compute the score for the sample meanthen determine whether the sample mean not places)

Answer 1

Answer: Your welcome!

Step-by-step explanation:

The sample mean is not an extreme value. To determine this, we can calculate the z-score for the sample mean. The z-score is calculated by subtracting the population mean from the sample mean, and then dividing by the population standard deviation.

z = (M - p) / (sigma / √n)

z = (60.7 - 42.6) / (12 / √36)

z = 0.81

Since the z-score is 0.81, which is within two standard deviations of the mean (z < 2), the sample mean is not an extreme value.