Question

Surface area of a cylinder radias 2yd hight is 8yd

Answer 1

125.7 yd² (nearest tenth)

Explanation:

The formula for the surface area of a cylinder is:

`\large\boxed{S.A.=2\pi r^2 + 2\pi r h}`

where:

• r is the radius of the circular base.
• h is the height of the cylinder.

To find the surface area of a cylinder with radius 2 yd and height 8 yd, substitute r = 2 and h = 8 into the formula and solve for S.A.:

`\begin{aligned}S.A.&=2\pi \cdot 2^2 + 2\pi \cdot 2\cdot 8\\&=2\pi \cdot 4 + 32\pi\\&=8\pi + 32\pi\\&=40\pi\\&=125.663706...\\&=125.7\; \sf yd^2\;(nearest\;tenth)\end{aligned}`

Therefore, the surface area of the cylinder is 125.7 yd² (rounded to the nearest tenth).