Question

2. The length of Sally's garden is 4 meters greater than 3 times the width. Theperimeter of her garden is 72 meters. Find the dimensions of Sally's garden.The garden has a width of 8 and a length of 28.

Answer 1

L = length

W = width

L = 4 + 3*W

The perimeter of a rectangle is the sum of its sides: 2L + 2W. Since it's 72, we have:

2L + 2W = 72

Now, to solve for L and W, the dimensions of the garden, we can use the first equation (L = 4 + 3*W) into the second one (2L + 2W = 72):

2L + 2W = 72

2 * (4 + 3*W) + 2W = 72

2 * 4 + 2 * 3W + 2W = 72

8 + 6W + 2W = 72

8W = 72 - 8

8W = 64

W = 64/8 = 8

Then we can use this result to find L:

L = 4 + 3W = 4 + 3 * 8 = 4 + 24 = 28

Therefore, the garden has a width of 8 and a length of 28.