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Find center of ellipse equation x2 + 4y2 - 4x + 24y +36 =0

User Jainil
by
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1 Answer

3 votes

Answer:

(2,-3)

Explanation:

x^2 - 4x + 4 + 4y^2 + 24y + 36 - 4 - 36 = 0

=> (x-2)^2 + 4(y+3)^2 = 16

Dividing both sides by 16, we get:

=> (x-2)^2/16 + 4(y+3)^2/16 = 1

Comparing this with the standard form equation above, we see that the center of the ellipse is (h, k) = (2, -3).

Therefore, the center of the ellipse is at the point (2, -3).

User Santosh B
by
8.1k points