Question

Choose the equation that represents the solutions of 0 = 0.25x² - 8x. 0.25± √(0.25)² - (4)(1)(-8) 2(1) O O X = X = X = X = -0.25± √√(0.25)² – (4)(1)(-8) 2(1) 8± √(-8)²-(4)(0.25) (0) 2(0.25) -8± √(-8)²-(4)(0.25)(0) 2(0.25)​

Answer 1

The question involves solving a quadratic equation using the quadratic formula. Once the equation is in standard form, the formula is applied with the appropriate values for a, b, and c to find the solutions for x.

Step-by-step explanation:

The student's question revolves around solving a quadratic equation, which is a standard topic in high school algebra. Specifically, the equation to be solved is 0 = 0.25x² - 8x. We can use the quadratic formula, which is x = √(-b±√(b²-4ac))/(2a), where a, b, and c are coefficients from the quadratic equation ax² + bx + c = 0. Applying the quadratic formula to the given equation, we identify a = 0.25, b = -8, and c = 0. Substituting these values into the formula provides the solutions for x.

To find the actual values of x, we calculate the determinant (b²-4ac), which is (-8)² - 4(0.25)(0) = 64. Then, we apply it to the quadratic formula to get x = √(8 ± √(64))/(2(0.25)). This simplifies to two potential solutions for x, which we can find by performing the arithmetic.