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X^2+5x−1=0, which number would have to be added to "complete the square"?

User Aligus
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Answer: To complete the square for the quadratic equation x^2 + 5x - 1 = 0, we need to add a constant term that will allow us to rewrite the left-hand side of the equation as a perfect square trinomial.

To determine this constant term, we take half of the coefficient of x, square it, and add it to both sides of the equation. The coefficient of x in this equation is 5, so we have:

(5/2)^2 = 6.25

Adding 6.25 to both sides of the equation, we get:

x^2 + 5x - 1 + 6.25 = 6.25

x^2 + 5x + 5.25 = 0

Now, we can factor this equation as:

(x + 2.5)^2 = 0.25

To solve for x, we take the square root of both sides and solve for x:

x + 2.5 = ±0.5

x = -2.5 ± 0.5

So, the number that had to be added to "complete the square" was 6.25.

Explanation:

User Mark Adams
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