Answer:
The equation that has the solution set (1, 3) is D. x² - 4x +3=0.
Explanation:
To find out which equation has the solution set (1, 3), we can substitute x = 1 and x = 3 into each equation and see which one gives us 0.
A. x² + 4x + 3 = 0
Substituting x = 1: (1)² + 4(1) + 3 = 8 ≠ 0
Substituting x = 3: (3)² + 4(3) + 3 = 24 ≠ 0
B. x² + 4x − 3 = 0
Substituting x = 1: (1)² + 4(1) − 3 = 2 ≠ 0
Substituting x = 3: (3)² + 4(3) − 3 = 18 ≠ 0
C. x² - 4x - 3 = 0
Substituting x = 1: (1)² - 4(1) - 3 = -6 ≠ 0
Substituting x = 3: (3)² - 4(3) - 3 = 0
D. x² - 4x +3=0
Substituting x = 1: (1)² - 4(1) + 3 = 0
Substituting x = 3: (3)² - 4(3) + 3 = 0
The equation that has the solution set (1, 3) is D. x² - 4x +3=0.