Question

if the 1700- lb boom ab , the 215- lb cage bcd , and the 164- lb man have centers of gravity located at points g1 , g2 and g3 , respectively, determine the resultant moment produced by all the weights about point a . (figure 1) express your answer to three significant figures and include the appropriate units. enter positive value if the moment is counterclockwise and negative value if the moment is clockwise.

Answer 1

Let's assume the distances between the points G1, G2, and G3 and point A are d1, d2, and d3, respectively. Then, the moment produced by each weight around point A can be calculated as follows:

Moment of AB = 1700 lb x d1

Moment of BCD = 215 lb x d2

Moment of man = 164 lb x d3

The resultant moment produced by all the weights about point A can be found by adding up these individual moments:

Resultant moment about A = (1700 lb x d1) + (215 lb x d2) + (164 lb x d3)

To express the answer in appropriate units, we need to convert pounds (lb) to a standard unit of force such as newtons (N) and inches (in) to meters (m).

Assuming 1 lb = 4.44822 N and 1 in = 0.0254 m, we get:

1700 lb = 7585.74 N

215 lb = 957.5125 N

164 lb = 730.7096 N

1 in = 0.0254 m

Substituting these values into the above equation, we get:

Resultant moment about A = (7585.74 N x d1) + (957.5125 N x d2) + (730.7096 N x d3)