Answer:
To prove that the medians to the legs of an isosceles triangle are congruent, we need to show that BT ≅ CS.
Proof:
We will start by drawing a diagram of the given isosceles triangle ABC with medians BT and CS.
[Insert a diagram of the isosceles triangle ABC with medians BT and CS]
Since AB ≅ AC, we know that angles B and C are congruent. Thus, we have:
∠BAC = ∠ABC = ∠ACB
Next, we will draw a line through point A parallel to BC and label the intersection point with BT as D.
[Insert a diagram of the isosceles triangle ABC with line AD parallel to BC]
Since AD is parallel to BC, we know that ∠BAD = ∠ACB (alternate interior angles) and ∠ADB = ∠ABC (corresponding angles). We also know that BD = DC (since BT is a median), so we have:
△ABD ≅ △ACD (by angle-angle-side)
Therefore, we have:
AD ≅ AD (reflexive property)
BD ≅ DC (given)
AB ≅ AC (given)
Thus, by the triangle congruence, we have BT ≅ CS (corresponding parts of congruent triangles are congruent).
Therefore, we have proved that the medians to the legs of an isosceles triangle are congruent.