Answer:
350 m/s
Step-by-step explanation:
Before the explosion, the rocket's momentum is given by:
p = m*v where
p = momentum
m = mass of the rocket
v = velocity of the rocket
Given that the mass of the rocket is 5 kg and its velocity is 200 m/s, we can calculate the momentum as:
p = m*v = 5 kg * 200 m/s = 1000 kg·m/s
After the explosion, the momentum is conserved, which means the total momentum of the two parts is still 1000 kg·m/s. We can use this principle to solve for the velocity of the second part.
Let v1 be the velocity of the 3 kg part, and v2 be the velocity of the other part. Since they are both moving in the same direction, we can write:
p = m1v1 + m2v2
where m1 = 3 kg is the mass of the first part, and m2 is the mass of the second part.
Substituting the known values, we get:
1000 kg·m/s = 3 kg * 100 m/s + m2 * v2
Solving for v2, we get:
v2 = (1000 kg·m/s - 300 kg·m/s) / m2
v2 = 700 kg·m/s / m2
We still need to find the mass of the second part. Since the rocket initially had a mass of 5 kg, and one part has a mass of 3 kg, the other part must have a mass of:
m2 = 5 kg - 3 kg = 2 kg
Substituting this into the equation for v2, we get:
v2 = 700 kg·m/s / 2 kg
v2 = 350 m/s
Therefore, the unknown speed of the other part is 350 m/s.