To answer this question, we need to know the concentration of the NaOH solution in terms of molarity (M) or normality (N). Without this information, it is not possible to calculate the mass of NaOH in 8 L of the solution.
For example, if the concentration of the NaOH solution is 1 M (one mole of NaOH per liter of solution), we can calculate the number of moles of NaOH present in 8 L of the solution:
moles of NaOH = M x volume of solution
moles of NaOH = 1 mol/L x 8 L
moles of NaOH = 8 mol
The molar mass of NaOH is approximately 40 g/mol. Therefore, the mass of NaOH present in 8 L of 1 M NaOH solution would be:
mass of NaOH = moles of NaOH x molar mass of NaOH
mass of NaOH = 8 mol x 40 g/mol
mass of NaOH = 320 g
If the concentration of the NaOH solution is different from 1 M, the calculation would involve multiplying the concentration by the volume of solution and then multiplying by the molar mass of NaOH.