To solve the inequality n(n-3) < 54, we can first rearrange it into standard quadratic form by bringing all the terms to one side:
n^2 - 3n - 54 < 0
Next, we can factor the quadratic expression:
(n - 9)(n + 6) < 0
To determine the values of n that satisfy this inequality, we can use the sign test. We evaluate the expression (n - 9)(n + 6) for some test values of n in each of the intervals (-∞, -6), (-6, 9), and (9, ∞) to determine the sign of the expression in each interval.
For example, if we choose n = -7 (which is in the interval (-∞, -6)), then we have:
(-7 - 9)(-7 + 6) = (-16)(-1) = 16 > 0
This tells us that the expression (n - 9)(n + 6) is positive in the interval (-∞, -6).
If we choose n = 0 (which is in the interval (-6, 9)), then we have:
(0 - 9)(0 + 6) = (-9)(6) = -54 < 0
This tells us that the expression (n - 9)(n + 6) is negative in the interval (-6, 9).
If we choose n = 10 (which is in the interval (9, ∞)), then we have:
(10 - 9)(10 + 6) = (1)(16) = 16 > 0
This tells us that the expression (n - 9)(n + 6) is positive in the interval (9, ∞).
Since the inequality (n - 9)(n + 6) < 0 is true only in the interval (-6, 9), we can conclude that the solution to the inequality n(n-3) < 54 is:
-6 < n < 9
Therefore, the number n that satisfies the inequality is any number between -6 and 9 (exclusive).