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A measuring cylinder is filled with 50ml of water Now a stone was immersed into the cylinder and the water level rose to 75ml.

What is the value of upthrust acting on the stone?Explain
What is the volume of the water displaced by the stone?

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1 Answer

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Step-by-step explanation:

The value of upthrust acting on the stone can be calculated by using Archimedes' principle, which states that the upthrust acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

To calculate the upthrust acting on the stone, we first need to find the weight of the water displaced by the stone. The volume of water displaced is equal to the difference between the initial volume of water (50 ml) and the final volume of water (75 ml), which is 25 ml.

The density of water is approximately 1 g/ml, so the mass of the water displaced is:

mass = density x volume

mass = 1 g/ml x 25 ml

mass = 25 g

The weight of the water displaced is:

weight = mass x gravity

weight = 25 g x 9.81 m/s^2

weight = 245.25 N (rounded to two decimal places)

Therefore, the upthrust acting on the stone is equal to 245.25 N.

The volume of the water displaced by the stone is 25 ml. This is because the stone has displaced an additional 25 ml of water, causing the water level to rise from 50 ml to 75 ml. The volume of water displaced is equal to the volume of the portion of the stone that is submerged in the water.

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