Answer:
See below for explanation since answer already provided along with question
Explanation:
When adding binary numbers just add them as you would decimal numbers starting at the rightmost bit.
Note for bit addition
0 + 0 = 0
0 + 1 = 1
1 + 0 = 1
1 + 1 = 0 with a carry of 1 which is added to the next left column
When subtracting bits
0 - 0 = 0
0 - 1 = 1 but requires a carry from the next left column
1 - 0 = 0
1 - 1 = 0
First 11011₂ + 10011₂
Add the right most bits 1 + 1 = 0 with a carry of 1
The next left column has 1 + 1 = 10 + 1 = 11 that means 1 with a carry of 1
The next left column has 0 + 0 = 0; add the carry to get 0 + 1 = 1; no carry
The next left column has 1 + 0 = 1; no carry
The left most column has 1 + 1 = 0 with a carry of 1 which is appended to the left most position
Reading from left to right this would be 1 0 1 1 1 0
(This is the same as adding two 2-digit numbers with a carry. For example, 74 + 82 = 156)
In long addition format:
The leading zeros above are only for alignment and do not affect the values . Note the addition result has 6 places whereas the items being added have only 5 places
Subtracting 1 1 1 0 1 will give
Here, starting at the right most column we get 0 - 1 = 1 which requires a carry from the next left column. So the bit in the next left column becomes 1 - 1 = 0 which makes that column 0 - 0 = 0
The next two columns on the left have both 1 so it is just 1 - 1 = 0 in both
In the next to last left column we have 0 - 1, this requires a carry from the left most column so it becomes 0 - 1 with carry = 10 - 1 = 1
Hope that was comprehensible