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Write a quadratic equation and solve using any algebraic method.The area of a rectangular carpet is 216 square feet. The length of the carpet is 3 feet more than three times the width of the carpet. What are the dimensions (length and width) of the carpet?

explain why?

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Answer: Let x be the width of the carpet in feet.

Then, the length of the carpet is 3 feet more than three times the width, which can be expressed as 3x + 3.

The area of a rectangle is given by the formula A = length × width. Therefore, the area of the carpet is:

A = (3x + 3) x = 3x² + 3x

We know that the area of the carpet is 216 square feet, so we can set up the equation:

3x² + 3x = 216

To solve for x, we can first divide both sides by 3:

x² + x = 72

Then, we can rearrange the equation to get it in standard quadratic form:

x² + x - 72 = 0

Now we can use the quadratic formula to solve for x:

x = (-b ± √(b² - 4ac)) / 2a

where a = 1, b = 1, and c = -72.

Plugging these values into the formula, we get:

x = (-1 ± √(1² - 4(1)(-72))) / 2(1)

x = (-1 ± √(1 + 288)) / 2

x = (-1 ± √289) / 2

x = (-1 ± 17) / 2

This gives us two possible values for x: x = -9 or x = 8.

Since the width of the carpet can't be negative, we reject the negative solution and conclude that the width of the carpet is 8 feet.

To find the length of the carpet, we can use the expression we found earlier: 3x + 3. Plugging in x = 8, we get:

length = 3(8) + 3 = 24 + 3 = 27

Therefore, the dimensions of the carpet are 8 feet by 27 feet.

Explanation:

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