Question

Y = -2(x + 1)²-3

x-ints:
y-int:
Domain:
Range:
Vertex:
Axis of symmetry:
Min or Max:
Transformation:
Mapping Notation:

y-3=-3(x+5)²-1
x-ints:
y-int:
Domain:
Range:
Vertex:
Axis of symmetry:
Min or Max:
Transformation:
Mapping Notation:

Answer 1

For the first equation, Y = -2(x + 1)²-3:

x-ints: None

y-int: (-3)

Domain: All real numbers

Range: (-∞, -3]

Vertex: (-1, -3)

Axis of symmetry: x = -1

Min or Max: Maximum

Transformation: Reflects the graph of y = 2x² over the y-axis, moves the vertex left by 1 unit and down by 3 units.

Mapping Notation: y ≤ -3

For the second equation, y-3=-3(x+5)²-1:

x-ints: None

y-int: 2

Domain: All real numbers

Range: (-∞, 2]

Vertex: (-5, 3)

Axis of symmetry: x = -5

Min or Max: Minimum

Transformation: Reflects the graph of y = 3x² over the y-axis, moves the vertex left by 5 units and up by 3 units.

Mapping Notation: y ≤ 2