Question

Coulomb's Law equation is:  FE = kq1q2/r2In this expression,  FE  is the electric force between charges q1  and q2 separated by distance r.When the signs of the charges are included for q1  and q2 , the evaluation of Coulomb's Law equation can yield a positive or negative answer for FE .What is the appropriate interpretation of the sign of the numeric evaluation of FE ?(A) If FE is negative, the charges are attracting.(B) If FE is positive, the charges are attracting.

Answer 1

We know like charges repel amd unlike charges attract.

Thus if one charge is positive and other is negative then both charges will attract each other.

So if the force is negative , the charges are attracting.

Thus the answer is:

(A) If FE is negative, the charges are attracting.