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You deposit $3100 in an account that earns 5% annual interest. Find the balance after 2 years if the interest is compounded with the given frequency.

A. quarterly
B. monthly
C. continuously

You deposit $3100 in an account that earns 5% annual interest. Find the balance after-example-1
User Xorsat
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A. Quarterly Compounding:

First, we need to calculate the quarterly interest rate, which is 5%/4 = 1.25%.

After the first quarter, the balance becomes:

3100 + (1.25% * 3100) = $3138.75

After the second quarter, the balance becomes:

3138.75 + (1.25% * 3138.75) = $3177.91

After the third quarter, the balance becomes:

3177.91 + (1.25% * 3177.91) = $3217.43

After the fourth quarter, the balance becomes:

3217.43 + (1.25% * 3217.43) = $3257.31

Therefore, the balance after 2 years with quarterly compounding is $3257.31.

B. Monthly Compounding:

First, we need to calculate the monthly interest rate, which is 5%/12 = 0.4167%.

After the first month, the balance becomes:

3100 + (0.4167% * 3100) = $3113.25

After the second month, the balance becomes:

3113.25 + (0.4167% * 3113.25) = $3126.53

After the twenty-fourth month, the balance becomes:

3335.08 + (0.4167% * 3335.08) = $3461.85

Therefore, the balance after 2 years with monthly compounding is $3461.85.

C. Continuous Compounding:

The formula for continuous compounding is:

A = Pe^(rt)

where A is the balance after time t, P is the principal, r is the interest rate, and e is the mathematical constant e (approximately equal to 2.71828).

Plugging in the values, we get:

A = 3100 * e^(0.05 * 2) = $3398.98

Therefore, the balance after 2 years with continuous compounding is $3398.98.

User Noobgineer
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