Answer: We can use the formula for heat (Q) gained or lost by an object undergoing a temperature change:
Q = mcΔT
where Q is the heat absorbed or released, m is the mass of the object, c is the specific heat of the object, and ΔT is the change in temperature.
We are given that a 28 g coin absorbs 658 J of heat while it increases in temperature from 25 to 125 °C. We can plug these values into the formula and solve for c:
658 J = (0.028 kg) * c * (125 °C - 25 °C)
Simplifying, we get:
658 J = 0.028 kg * c * 100 °C
Dividing both sides by (0.028 kg * 100 °C), we get:
c = 658 J / (0.028 kg * 100 °C)
c ≈ 234.6 J/(kg·°C)
Therefore, the specific heat of the metal in the coin is approximately 234.6 J/(kg·°C).
Explanation: