Question

2. Consider the reaction of zinc metal with hydrochloric acid (HCl)

a. Write the equation for this reaction, then balance the equation.

b. Calculate the moles of hydrochloric acid (HCl) produced if 3.57 grams of zinc react completely

Answer 1

a. The balanced equation for the reaction of zinc metal with hydrochloric acid (HCl) is:

Zn + 2HCl → ZnCl2 + H2

b. We can use stoichiometry to calculate the moles of hydrochloric acid (HCl) produced from 3.57 grams of zinc. First, we need to determine the number of moles of zinc using its molar mass:

molar mass of Zn = 65.38 g/mol

moles of Zn = 3.57 g / 65.38 g/mol = 0.0546 mol

From the balanced equation, we know that for every mole of zinc, two moles of hydrochloric acid are consumed. Therefore, the number of moles of hydrochloric acid produced is:

moles of HCl = 2 x 0.0546 mol = 0.1092 mol

So, 3.57 grams of zinc would produce 0.1092 moles of hydrochloric acid.