Answer:
Task 1:
The roller coaster is modeled by a half-circle with the center at the origin and a highest point of 30 feet above the ground. The general equation of a circle with the center at the origin is x^2 + y^2 = r^2, where r is the radius of the circle. Since the roller coaster is a half-circle, the radius of the circle is 30 feet. Thus, the equation of the roller coaster is:
x^2 + y^2 = 30^2
x^2 + y^2 = 900
Task 2:
To solve for y, we isolate y and take the square root of both sides. Since we are only interested in the positive root, we get:
y = sqrt(900 - x^2)
Task 3:
The graph of the roller coaster is shown below:
Task 4:
To find the horizontal distance each beam is from the origin, we need to solve for x in the equation of the circle when y = 25. Substituting y = 25, we get:
x^2 + 25^2 = 900
x^2 = 400
x = ± 20
Since we are only interested in the positive value of x, the horizontal distance each beam is from the origin is 20 feet.
Task 5:
We need to place the two beams equidistant from the axis of symmetry of the roller coaster, which is the y-axis. Therefore, we place one beam at (20, 0) and the other beam at (-20, 0).
Task 6:
The cable is modeled by the equation y = -x + 30 and the strut is modeled by the equation y = -x/3. The graph of the cable and the strut on the model of the roller coaster is shown below:Task 7:
To find the point where the cable and the strut intersect, we need to solve the system of equations:
y = -x + 30
y = -x/3
Substituting the second equation into the first equation, we get:
-x/3 = -x + 30
2x/3 = 30
x = 45
Substituting x = 45 into the second equation, we get:
y = -x/3
y = -45/3
y = -15
Therefore, the cable and the strut intersect at the point (45, -15). This means that the cable and the strut intersect 15 feet below the ground level of the roller coaster at a horizontal distance of 45 feet from the origin.
Task 8:
The two struts are modeled by the equations y = 10x/3 and y = -10x/3. The graph of the two struts on the model of the roller coaster is shown below:
Task 9:
To find the x-value of where the beam should be placed, we need to find the intersection point of the two struts when they are 2 feet apart. We can set the two equations equal to each other and solve for x:
10x/3 = -10x/3 + 2
20x/3 = 2
x = 3/10
Therefore, the reinforcement beam should be placed at a horizontal distance of 3/10 feet from the origin.
Task 10:
We need to place the vertical reinforcement beam at a horizontal distance of
Explanation: